Correct. You can find the roots of this equation by factoring: $\displaystyle{y}={{x}}^{{2}}-{2}{x}-{3}={\left({x}-{3}\right)}{\left({x}+{1}\right)}\usepackage{cmbright}\Huge\$ . The roots of the equation occur when $\displaystyle{y}={0}\usepackage{cmbright}\Huge\$ , so set each factor equal to 0 and solve. $\displaystyle{x}-{3}={0}\usepackage{cmbright}\Huge\$ , so $\displaystyle{x}={3}\usepackage{cmbright}\Huge\$ ; $\displaystyle{x}+{1}={0}\usepackage{cmbright}\Huge\$ , so $\displaystyle{x}=-{1}\usepackage{cmbright}\Huge\$ .