Incorrect. You can find the roots of this equation by factoring: $\displaystyle{y}={{x}}^{{2}}-{2}{x}-{3}={\left({x}-{3}\right)}{\left({x}+{1}\right)}\usepackage{cmbright}\Huge\$ . Now set $\displaystyle{y}={0}\usepackage{cmbright}\Huge\$ and solve each factor for x.