Correct. Factor out 8 and set the equation to zero: $\displaystyle{{x}}^{{2}}-{6}{x}+{4}={0}\usepackage{cmbright}\Huge\$ ; now use completing the square to find the roots. Rewrite the equation as $\displaystyle{{x}}^{{2}}-{6}{x}=-{4}\usepackage{cmbright}\Huge\$ and add 9 to both sides to create a perfect square: $\displaystyle{{x}}^{{2}}-{6}{x}+{9}=-{4}+{9}\usepackage{cmbright}\Huge\$ . This creates $\displaystyle{{\left({x}-{3}\right)}}^{{2}}={5}\usepackage{cmbright}\Huge\$ , so the roots are $\displaystyle{x}={3}+\sqrt{{{5}}}\usepackage{cmbright}\Huge\$ and $\displaystyle{x}={3}-\sqrt{{{5}}}\usepackage{cmbright}\Huge\$ .