Correct. Factor out 9 and set the equation to zero: $\displaystyle{{x}}^{{2}}+{12}{x}-{3}={0}\usepackage{cmbright}\Huge\$ ; now use completing the square to find the roots. Rewrite the equation as $\displaystyle{{x}}^{{2}}+{12}{x}={3}\usepackage{cmbright}\Huge\$ and add 36 to both sides to create a perfect square: $\displaystyle{{x}}^{{2}}+{12}{x}+{36}={3}+{36}\usepackage{cmbright}\Huge\$ . This creates $\displaystyle{{\left({x}+{6}\right)}}^{{2}}={39}\usepackage{cmbright}\Huge\$ , so the roots are $\displaystyle{x}=-{6}+\sqrt{{{39}}}\usepackage{cmbright}\Huge\$ and $\displaystyle{x}=-{6}-\sqrt{{{39}}}\usepackage{cmbright}\Huge\$ .