Incorrect. You can factor out 9, leaving $\displaystyle{9}{\left({{x}}^{{2}}+{12}{x}-{3}\right)}\usepackage{cmbright}\Huge\$ . Removing the 9 and setting the remaining equation equal to zero gives you $\displaystyle{{x}}^{{2}}+{12}{x}-{3}={0}\usepackage{cmbright}\Huge\$ . Rewrite the equation so that the left side has the form $\displaystyle{{x}}^{{2}}+{b}{x}\usepackage{cmbright}\Huge\$ . What number will complete the square? Add this number to both sides and write the left side as a binomial squared. Then, take the square roots of both sides, noting both positive and negative possibilities, and solve for x.