Incorrect. Remember that the quadratic formula is $\displaystyle{x}=\frac{{-{b}\pm\sqrt{{{{b}}^{{2}}-{4}{a}{c}}}}}{{{2}{a}}}\usepackage{cmbright}\Huge\$ . You can use the term $\displaystyle{2}{a}={12}\usepackage{cmbright}\Huge\$ to find the value for a, and then use the term $\displaystyle{4}{a}{c}={72}\usepackage{cmbright}\Huge\$ to find the value of c. Notice that in finding the value of b, you cannot reliably use $\displaystyle{{b}}^{{2}}\usepackage{cmbright}\Huge\$ , as this could be either a positive or negative value.