Correct. In the equation $\displaystyle{7}{{x}}^{{2}}+{8}{x}-{5}={0}\usepackage{cmbright}\Huge\$ , $\displaystyle{a}={7},{b}={8},\usepackage{cmbright}\Huge\$ and $\displaystyle{c}=-{5}\usepackage{cmbright}\Huge\$ , so $\displaystyle{x}=\frac{{-{8}\pm\sqrt{{{{8}}^{{2}}-{4}{\left({7}\right)}{\left(-{5}\right)}}}}}{{{2}{\left({7}\right)}}}\usepackage{cmbright}\Huge\$ .