Correct. When $\displaystyle{a}={3},{b}={6}\usepackage{cmbright}\Huge\$ , and $\displaystyle{c}={1}\usepackage{cmbright}\Huge\$ , $\displaystyle{x}=\frac{{-{\left({6}\right)}\pm\sqrt{{{{\left({6}\right)}}^{{2}}-{4}{\left({3}\right)}{\left({1}\right)}}}}}{{{2}{\left({3}\right)}}}\usepackage{cmbright}\Huge\$ . This can be simplified to $\displaystyle{x}=\frac{{-{6}\pm\sqrt{{{36}-{12}}}}}{{{6}}}=\frac{{-{6}\pm\sqrt{{{24}}}}}{{2}}=\frac{{-{6}\pm{2}\sqrt{{6}}}}{{6}}\usepackage{cmbright}\Huge\$ , so $\displaystyle{x}=\frac{{-{6}+{2}\sqrt{{6}}}}{{6}}\usepackage{cmbright}\Huge\$ and $\displaystyle{x}=\frac{{-{6}-{2}\sqrt{{6}}}}{{6}}\usepackage{cmbright}\Huge\$ .