Correct. Evaluating $\displaystyle{{b}}^{{2}}-{4}{a}{c}\usepackage{cmbright}\Huge\$ for this equation, you find that $\displaystyle{{\left({2}\right)}}^{{2}}-{4}{\left({7}\right)}{\left(-{5}\right)}={4}+{140}={144}\usepackage{cmbright}\Huge\$ , which is greater than zero. This means that the quadratic equation has two solutions.