Correct. If you evaluate $\displaystyle{{b}}^{{2}}-{4}{a}{c}\usepackage{cmbright}\Huge\$ for this equation, you find that $\displaystyle{{\left({8}\right)}}^{{2}}-{4}{\left({1}\right)}{\left({16}\right)}={64}-{64}={0}\usepackage{cmbright}\Huge\$ , so the quadratic equation has one solution. Because the coefficient in the first term is positive, you know that the parabola will open upward.