Incorrect. First, rewrite the equation: $\displaystyle{3}{{x}}^{{2}}-{9}{x}+{6}={0}\usepackage{cmbright}\Huge\$ . If the polynomial can be factored, its factored form will be $\displaystyle{\left({3}{x}+{r}\right)}{\left({x}+{s}\right)}\usepackage{cmbright}\Huge\$ where $\displaystyle{r}{s}={6}\usepackage{cmbright}\Huge\$ and $\displaystyle{r}+{3}{s}=-{9}\usepackage{cmbright}\Huge\$ . You might also notice that each term is a multiple of 3, so a 3 can be factored out of the polynomial. In either case, factor the polynomial and use the zero product property to solve for x.