Correct. $\displaystyle\frac{{{2}{{x}}^{{2}}+{10}}}{{{3}{{x}}^{{2}}+{15}}}=\frac{{{2}{\left({{x}}^{{2}}+{5}\right)}}}{{{3}{\left({{x}}^{{2}}+{5}\right)}}}\usepackage{cmbright}\Huge\$ . Pulling out the common factor $\displaystyle{{x}}^{{2}}+{5}\usepackage{cmbright}\Huge\$ , you are left with $\displaystyle\frac{{2}}{{3}}\usepackage{cmbright}\Huge\$ .