Correct. Substituting the values $\displaystyle{a}={2},{b}={8},\usepackage{cmbright}\Huge\$ and $\displaystyle{c}=-{15}\usepackage{cmbright}\Huge\$ into the quadratic formula, you found that $\displaystyle{x}=\frac{{-{4}+\sqrt{{{46}}}}}{{2}}\usepackage{cmbright}\Huge\$ or $\displaystyle{x}=\frac{{-{4}-\sqrt{{{46}}}}}{{2}}\usepackage{cmbright}\Huge\$ .