Correct. Substituting the values $\displaystyle{a}={1},{b}={6},\usepackage{cmbright}\Huge\$ and $\displaystyle{c}={9}\usepackage{cmbright}\Huge\$ into the quadratic formula, you found that $\displaystyle{x}=-{3}\usepackage{cmbright}\Huge\$ . Notice that this equation can also be factored without using the quadratic formula: $\displaystyle{{x}}^{{2}}+{6}{x}+{9}={\left({x}+{3}\right)}{\left({x}+{3}\right)}.\usepackage{cmbright}\Huge\$