Correct. You recognized that $\displaystyle\frac{{{\left({x}+{2}\right)}{\left({x}-{5}\right)}}}{{{{x}}^{{2}}+{7}{x}+{10}}}=\frac{{{\left({x}+{2}\right)}{\left({x}-{5}\right)}}}{{{\left({x}+{2}\right)}{\left({x}+{5}\right)}}}\usepackage{cmbright}\Huge\$ . $\displaystyle\frac{{{x}+{2}}}{{{x}+{2}}}={1}\usepackage{cmbright}\Huge\$ , so $\displaystyle\frac{{{\left({x}+{2}\right)}{\left({x}-{5}\right)}}}{{{\left({x}+{2}\right)}{\left({x}+{5}\right)}}}={1}\cdot\frac{{{x}-{5}}}{{{x}+{5}}}=\frac{{{x}-{5}}}{{{x}+{5}}}\usepackage{cmbright}\Huge\$ .