Correct. $\displaystyle\frac{{-{{x}}^{{3}}+{2}{{x}}^{{2}}+{3}{x}}}{{{3}{{x}}^{{3}}-{6}{{x}}^{{2}}-{9}{x}}}=\frac{{-{x}{\left({x}+{1}\right)}{\left({x}-{3}\right)}}}{{{3}{x}{\left({x}+{1}\right)}{\left({x}-{3}\right)}}}\usepackage{cmbright}\Huge\$ , so the domain of the expression excludes $\displaystyle{x}={0}\usepackage{cmbright}\Huge\$ , $\displaystyle{x}=-{1}\usepackage{cmbright}\Huge\$ , and $\displaystyle{x}={3}\usepackage{cmbright}\Huge\$ . Simplifying the expression, you find that $\displaystyle\frac{{-{x}{\left({x}+{1}\right)}{\left({x}-{3}\right)}}}{{{3}{x}{\left({x}+{1}\right)}{\left({x}-{3}\right)}}}=-\frac{{1}}{{3}}\usepackage{cmbright}\Huge\$ .