Correct. $\displaystyle\frac{{{3}{{x}}^{{2}}-{30}{x}+{75}}}{{{9}{{x}}^{{2}}+{45}}}=\frac{{{3}{{\left({x}-{5}\right)}}^{{2}}}}{{{9}{\left({{x}}^{{2}}+{5}\right)}}}\usepackage{cmbright}\Huge\$ . Since there is no value for x that will make $\displaystyle{{x}}^{{2}}+{5}={0}\usepackage{cmbright}\Huge\$ , the domain includes all values for x. Simplifying the expression, you find that $\displaystyle\frac{{{3}{{\left({x}-{5}\right)}}^{{2}}}}{{{9}{\left({{x}}^{{2}}+{5}\right)}}}=\frac{{{\left({x}-{5}\right)}}^{{2}}}{{{3}{\left({{x}}^{{2}}+{5}\right)}}}\usepackage{cmbright}\Huge\$ .