Correct. The parabola has a y-intercept at $\displaystyle\frac{{3}}{{2}}\usepackage{cmbright}\Huge\$ , and it opens downward and wide, reflecting the term $\displaystyle-\frac{{1}}{{3}}{{x}}^{{2}}\usepackage{cmbright}\Huge\$ . In the linear function, $\displaystyle{y}\usepackage{cmbright}\Huge\$ decreases as $\displaystyle{x}\usepackage{cmbright}\Huge\$ increases, reflecting the negative slope.