Correct. This expression is equivalent to $\displaystyle\frac{{{\left({b}+{1}\right)}}^{{2}}}{{b}}\cdot\frac{{{b}{\left({b}-{1}\right)}}}{{{\left({b}+{1}\right)}{\left({b}-{1}\right)}}}\usepackage{cmbright}\Huge\$ , so the domain excludes the values $\displaystyle{b}={0}\usepackage{cmbright}\Huge\$ , -1, and 1 since those values would yield a denominator of 0. The expression simplifies to $\displaystyle{b}+{1}\usepackage{cmbright}\Huge\$ .