Correct. This expression is equivalent to $\displaystyle\frac{{{\left({n}-{2}\right)}{\left({n}+{2}\right)}}}{{{n}{\left({n}-{2}\right)}}}\cdot\frac{{n}}{{{\left({n}+{8}\right)}{\left({n}+{2}\right)}}}\usepackage{cmbright}\Huge\$ , so the domain excludes the values $\displaystyle{n}={0}\usepackage{cmbright}\Huge\$ , 2, and -8 since those values would yield a denominator of 0. The expression simplifies to $\displaystyle\frac{{1}}{{{n}+{8}}}\usepackage{cmbright}\Huge\$ .