Correct. Adding the expressions and then factoring, you find that $\displaystyle\frac{{{{x}}^{{2}}+{4}{x}}}{{{x}+{3}}}+\frac{{{x}+{6}}}{{{x}+{3}}}=\frac{{{{x}}^{{2}}+{5}{x}+{6}}}{{{x}+{3}}}=\frac{{{\left({x}+{3}\right)}{\left({x}+{2}\right)}}}{{{x}+{3}}}={\left({x}+{2}\right)}\usepackage{cmbright}\Huge\$ .