Incorrect. Notice that both fractions share the same denominator. This means that $\displaystyle\frac{{{2}{\left({3}{x}+{1}\right)}}}{{{x}+{3}}}+\frac{{{3}{x}+{7}}}{{{x}+{3}}}=\frac{{{2}{\left({3}{x}+{1}\right)}+{3}{x}+{7}}}{{{x}+{3}}}\usepackage{cmbright}\Huge\$ . Collect like terms in the numerator and then simplify the fraction.