Incorrect. $\displaystyle\frac{{8}}{{x}}\usepackage{cmbright}\Huge\$ and $\displaystyle\frac{{{x}+{1}}}{{3}}\usepackage{cmbright}\Huge\$ have a common denominator of $\displaystyle{3}{x}\usepackage{cmbright}\Huge\$ , so this expression can be rewritten as $\displaystyle\frac{{{3}{\left({8}\right)}}}{{{3}{\left({x}\right)}}}+\frac{{{x}{\left({x}+{1}\right)}}}{{{x}{\left({3}\right)}}}\usepackage{cmbright}\Huge\$ . Now that they have a common denominator of $\displaystyle{3}{x}\usepackage{cmbright}\Huge\$ , add the numerators and simplify.