Correct. The common denominator of $\displaystyle\frac{{{2}{x}}}{{y}}\usepackage{cmbright}\Huge\$ and $\displaystyle\frac{{{2}{y}}}{{x}}\usepackage{cmbright}\Huge\$ is $\displaystyle{x}{y}\usepackage{cmbright}\Huge\$ , so $\displaystyle\frac{{{2}{x}}}{{y}}-\frac{{{2}{y}}}{{x}}=\frac{{{\left({x}\right)}{2}{x}}}{{{\left({x}\right)}{y}}}-\frac{{{\left({y}\right)}{2}{y}}}{{{\left({y}\right)}{x}}}=\frac{{{2}{{x}}^{{2}}-{2}{{y}}^{{2}}}}{{{x}{y}}}\usepackage{cmbright}\Huge\$ .