Correct. Identifying a common denominator of $\displaystyle{5}{\left({x}-{3}\right)}\usepackage{cmbright}\Huge\$ , you can rewrite the equation as $\displaystyle\frac{{{5}{x}}}{{{5}{\left({x}-{3}\right)}}}=\frac{{{2}{\left({x}-{3}\right)}}}{{{5}{\left({x}-{3}\right)}}}\usepackage{cmbright}\Huge\$ . If $\displaystyle{5}{x}={2}{x}-{6}\usepackage{cmbright}\Huge\$ , then $\displaystyle{3}{x}=-{6}\usepackage{cmbright}\Huge\$ , and $\displaystyle{x}=-{2}\usepackage{cmbright}\Huge\$ .