Correct. Identifying a common denominator of $\displaystyle{4}{{y}}^{{2}}\usepackage{cmbright}\Huge\$ , you can rewrite the equation as $\displaystyle\frac{{20}}{{{4}{{y}}^{{2}}}}=\frac{{{4}{y}}}{{{4}{{y}}^{{2}}}}\usepackage{cmbright}\Huge\$ . Solving the equation for y, you find $\displaystyle{y}={5}\usepackage{cmbright}\Huge\$ .