Correct. After multiplying both sides of the equation by the common denominator $\displaystyle{m}{\left({m}+{2}\right)}\usepackage{cmbright}\Huge\$ , you find $\displaystyle{2}{\left({m}+{2}\right)}={m}{\left({m}-{1}\right)}\usepackage{cmbright}\Huge\$ , or $\displaystyle{2}{m}+{4}={{m}}^{{2}}-{m}\usepackage{cmbright}\Huge\$ . This can be rearranged into the polynomial $\displaystyle{0}={{m}}^{{2}}-{3}{m}-{4}\usepackage{cmbright}\Huge\$ , which can be factored as $\displaystyle{\left({m}-{4}\right)}{\left({m}+{1}\right)}={0}\usepackage{cmbright}\Huge\$ .