Correct. Substituting values in for x, you find that x can be an integer, whole number, or natural number and still satisfy the description that $\displaystyle-\frac{{1}}{{2}}\cdot{x}\usepackage{cmbright}\Huge\$ yields an integer. When $\displaystyle{x}={6}\usepackage{cmbright}\Huge\$ (a whole number, natural number, and an integer), $\displaystyle-\frac{{1}}{{2}}\cdot{6}=-{3}\usepackage{cmbright}\Huge\$ , which is an integer.