Incorrect. The answer will be $\displaystyle\frac{{A}}{{B}}\usepackage{cmbright}\Huge\$ where A is the number of 2-digit numbers with a 5 in the tens digit and B is the number of 2-digit numbers. Both of these values can be computed by applying the Fundamental Counting Principle. There are 10 2-digit numbers that have a 5 in the tens place (since the ones digit can be anything between 0 and 9). How many 2-digit numbers are there? Be sure that your answer is a reduced fraction.