Correct. Dividing both sides by 3, the statement can be rewritten $\displaystyle{{\left(-{x}\right)}}^{{2}}>-{2}\usepackage{cmbright}\Huge\$ . You know that $\displaystyle{{\left(-{x}\right)}}^{{2}}\usepackage{cmbright}\Huge\$ is the same as x, so you are left with $\displaystyle{{x}}^{{2}}>-{2}\usepackage{cmbright}\Huge\$ . This is a true statement for all real numbers.