Incorrect. Order doesn't matter, so we need to take that into consideration when we make our calculation. There are 15 ways to choose the first captain and 14 ways to choose the second captain, so there are $\displaystyle{15}\cdot{14}={210}\usepackage{cmbright}\Huge\$ ways to choose the two captains in order. Since order doesn’t matter, we need to divide by 2 (the number of ways to “arrange” the 2 captains). Therefore, the answer is $\displaystyle\frac{{201}}{{2}}={105}\usepackage{cmbright}\Huge\$ .