Incorrect. If you substitute $\displaystyle{4}{{x}}^{{2}}+{12}{x}-{12}\usepackage{cmbright}\Huge\$ in for y in the second equation, you find $\displaystyle{4}{{x}}^{{2}}+{12}{x}-{12}={{x}}^{{2}}-{6}{x}+{9}\usepackage{cmbright}\Huge\$ . Now collect like terms, set the trinomial equal to 0, and factor. Once you have a value(s) for x, how do you find y?