Correct. By combining the two equations, you find that $\displaystyle{2}{y}={72}\usepackage{cmbright}\Huge\$ , and therefore $\displaystyle{y}={36}\usepackage{cmbright}\Huge\$ . Substituting $\displaystyle{y}={36}\usepackage{cmbright}\Huge\$ into the first equation, you get $\displaystyle{36}={2}{{x}}^{{2}}-{36}\usepackage{cmbright}\Huge\$ , so $\displaystyle{{x}}^{{2}}={36}\usepackage{cmbright}\Huge\$ , or $\displaystyle{x}=\pm{6}\usepackage{cmbright}\Huge\$ . The solutions are $\displaystyle{\left(-{6},{36}\right)}\usepackage{cmbright}\Huge\$ and $\displaystyle{\left({6},{36}\right)}\usepackage{cmbright}\Huge\$ .