Correct. There are $\displaystyle{4}\cdot{48}={192}\usepackage{cmbright}\Huge\$ ways to get a King and a non-King and there are $\displaystyle\frac{{{52}}}{{{502}}}={1326}\usepackage{cmbright}\Huge\$ two-card combinations, so the probability of getting a King and a non-King is $\displaystyle\frac{{192}}{{1326}}=\frac{{32}}{{221}}\usepackage{cmbright}\Huge\$ .