Correct. There are $\displaystyle{13}\cdot{39}={507}\usepackage{cmbright}\Huge\$ ways to get a Heart and a non-Heart and there are $\displaystyle\frac{{{52}}}{{{502}}}={1326}\usepackage{cmbright}\Huge\$ two-card combinations, so the probability of getting a Heart and a non-Heart is $\displaystyle\frac{{507}}{{1326}}=\frac{{13}}{{34}}\usepackage{cmbright}\Huge\$ .