Correct. The area of the flag is $\displaystyle{2}\cdot{1}={2}\usepackage{cmbright}\Huge\$ . Adding a border of width x, the new area of the flag is $\displaystyle{\left({2}+{2}{x}\right)}{\left({1}+{2}{x}\right)}\usepackage{cmbright}\Huge\$ . The area of the border is given by $\displaystyle{\left({2}+{2}{x}\right)}{\left({1}+{2}{x}\right)}-{\left({2}\right)}{\left({1}\right)}\usepackage{cmbright}\Huge\$ , and is equal to the total area of the border, 10. Simplifying the equation gives you $\displaystyle{4}{{x}}^{{2}}+{6}{x}-{10}={0}\usepackage{cmbright}\Huge\$ .