Correct. The probability that Robot A first finishes first is $\displaystyle\frac{{1}}{{10}}\usepackage{cmbright}\Huge\$ . The probability that one of the other two robots finishes second is $\displaystyle\frac{{2}}{{9}}\usepackage{cmbright}\Huge\$ ; this means the robot that does not finish second has a $\displaystyle\frac{{1}}{{8}}\usepackage{cmbright}\Huge\$ chance of finishing third. Multiply these probabilities to find the probabilities that they all occur. $\displaystyle{\left(\frac{{1}}{{10}}\right)}{\left(\frac{{2}}{{9}}\right)}{\left(\frac{{1}}{{8}}\right)}=\frac{{2}}{{720}}=\frac{{1}}{{360}}\usepackage{cmbright}\Huge\$ .