Incorrect. Robot A has a $\displaystyle\frac{{1}}{{10}}\usepackage{cmbright}\Huge\$ chance of finishing first, and then Robot B or Robot C has a $\displaystyle\frac{{2}}{{9}}\usepackage{cmbright}\Huge\$ chance of finishing second. What is the probability that the robot that does not finish second will finish third? Compute the finish of each robot as separate probabilities and then multiply.