A marble is launched upward at 32 feet per second from a platform that is 15 feet tall. Find the maximum height the marble reaches.

Use the equation $\displaystyle{h}=-{16}{{t}}^{{2}}+{v}_{{o}}{t}+{h}_{{o}}\usepackage{cmbright}\Huge\$ (where h=height, t=time, $\displaystyle{v}_{{o}}\usepackage{cmbright}\Huge\$ =initial velocity, and $\displaystyle{h}_{{o}}\usepackage{cmbright}\Huge\$ =initial height).