Correct. Substituting in the initial velocity and height, the equation can be rewritten as $\displaystyle{h}=-{16}{\left({{t}}^{{2}}-{8}{t}\right)}+{136}\usepackage{cmbright}\Huge\$ . Rewriting the equation to generate a perfect square gives you $\displaystyle{h}+{\left(-{16}{\left({16}\right)}\right)}=-{16}{\left({{t}}^{{2}}-{8}{t}+{16}\right)}+{136}\usepackage{cmbright}\Huge\$ . Simplifying the equation and solving for h yields $\displaystyle{h}=-{16}{{\left({t}-{4}\right)}}^{{2}}+{392}\usepackage{cmbright}\Huge\$ .