Correct. $\displaystyle\frac{{6}}{{24}}=\frac{{1}}{{4}}\usepackage{cmbright}\Huge\$ , but $\displaystyle\frac{{2}}{{10}}=\frac{{1}}{{5}}\usepackage{cmbright}\Huge\$ , and $\displaystyle\frac{{1}}{{4}}\ne\frac{{1}}{{5}}\usepackage{cmbright}\Huge\$ .