Correct. Simplifying this expression using the rules of exponents, you find that $\displaystyle{{\left({{a}}^{{2}}{{b}}^{{3}}{{c}}^{{-{{5}}}}\right)}}^{{4}}\cdot{{\left({a}{{b}}^{{2}}{c}\right)}}^{{4}}=\frac{{{{a}}^{{12}}{{b}}^{{20}}}}{{{c}}^{{16}}}\usepackage{cmbright}\Huge\$ .