Correct. Following the machine, you found that it would do the following operations: $\displaystyle{4}+{2}={6}\usepackage{cmbright}\Huge\$ , $\displaystyle{6}\cdot{6}={36}\usepackage{cmbright}\Huge\$ , and finally $\displaystyle{36}\div{3}={12}\usepackage{cmbright}\Huge\$ . The program would produce the number 12.