Use elimination to solve each system below.

System 1
$\displaystyle{2}{x}+{3}{y}={6}\usepackage{cmbright}\Huge\$
$\displaystyle-{2}{x}-{y}=-{6}\usepackage{cmbright}\Huge\$
System 2
$\displaystyle{2}{x}+{3}{y}={6}\usepackage{cmbright}\Huge\$
$\displaystyle{x}+{y}={4}\usepackage{cmbright}\Huge\$
Enter the values of x and y in the solution for each system in the following table.