Add the two negative numbers first. $\displaystyle{\left|-{2}\frac{{1}}{{3}}\right|}+{\left|-\frac{{5}}{{6}}\right|}={2}\frac{{1}}{{3}}+\frac{{5}}{{6}}=\frac{{14}}{{6}}+\frac{{5}}{{6}}=\frac{{19}}{{6}}={3}\frac{{1}}{{6}}\usepackage{cmbright}\Huge\$

Since the addends are negative, that sum is $\displaystyle-{3}\frac{{1}}{{6}}\usepackage{cmbright}\Huge\$ . Add this to $\displaystyle{7}\frac{{3}}{{4}}\usepackage{cmbright}\Huge\$ by finding the difference of their absolute values: $\displaystyle{7}\frac{{3}}{{4}}-{3}\frac{{1}}{{6}}={7}\frac{{9}}{{12}}-{3}\frac{{2}}{{12}}={4}\frac{{7}}{{12}}\usepackage{cmbright}\Huge\$ . Since $\displaystyle{7}\frac{{3}}{{4}}>{3}\frac{{1}}{{6}}\usepackage{cmbright}\Huge\$ , the answer is positive.