Correct. $\displaystyle{6}{p}+{8}-{8}\le{2}-{8}\usepackage{cmbright}\Huge\$ , so $\displaystyle{6}{p}\le-{6}\usepackage{cmbright}\Huge\$ . Then $\displaystyle\frac{{{6}{p}}}{{6}}\le\frac{{-{6}}}{{6}}\usepackage{cmbright}\Huge\$ , so $\displaystyle{p}\le-{1}\usepackage{cmbright}\Huge\$ .

Plot a closed circle at $\displaystyle-{1}\usepackage{cmbright}\Huge\$ and extend the shaded arrow to the left.