Correct. You need to first apply the order of operations to the numerator, then to the denominator, and finally divide.

$\displaystyle\frac{{{14}+{{3}}^{{2}}\cdot{4}}}{{{2}{\left({3}+{\left(-{2}\right)}\right)}}}=\frac{{{14}+{9}\cdot{4}}}{{{2}{\left({3}+{\left(-{2}\right)}\right)}}}=\frac{{{14}+{36}}}{{{2}{\left({3}+{\left(-{2}\right)}\right)}}}=\frac{{50}}{{{2}{\left({3}+{\left(-{2}\right)}\right)}}}=\frac{{50}}{{{2}{\left({1}\right)}}}=\frac{{50}}{{2}}={25}\usepackage{cmbright}\Huge\$