Correct. Find the difference of the absolute values of the fractions.

$\displaystyle{\left|-{47}\frac{{1}}{{6}}\right|}-{\left|{24}\frac{{3}}{{8}}\right|}={47}\frac{{1}}{{6}}-{24}\frac{{3}}{{8}}={47}\frac{{4}}{{24}}-{24}\frac{{9}}{{24}}={46}\frac{{28}}{{24}}-{24}\frac{{9}}{{24}}={22}\frac{{19}}{{24}}\usepackage{cmbright}\Huge\$

The number with the greater absolute value is negative, so the sum is negative.