Incorrect. Find $\displaystyle{47}\frac{{1}}{{6}}-{24}\frac{{3}}{{8}}\usepackage{cmbright}\Huge\$ . Give the answer the same sign as the number with the greater absolute value. The sum is $\displaystyle-{22}\frac{{19}}{{24}}\usepackage{cmbright}\Huge\$ , so the correct answer is $\displaystyle-{22}\usepackage{cmbright}\Huge\$ .