Correct. First add $\displaystyle{4}+{\left(-{1}\right)}\usepackage{cmbright}\Huge\$ . Since $\displaystyle{4}-{1}={3}\usepackage{cmbright}\Huge\$ , and $\displaystyle{4}>{1}\usepackage{cmbright}\Huge\$ , then $\displaystyle{4}+{\left(-{1}\right)}={3}\usepackage{cmbright}\Huge\$ . Now rewrite $\displaystyle{3}-{\left(-{2}\right)}\usepackage{cmbright}\Huge\$ as $\displaystyle{3}+{2}={5}\usepackage{cmbright}\Huge\$ .